490b^2-140b+10=0

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Solution for 490b^2-140b+10=0 equation:


Simplifying
490b2 + -140b + 10 = 0

Reorder the terms:
10 + -140b + 490b2 = 0

Solving
10 + -140b + 490b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '10'.
10(1 + -14b + 49b2) = 0

Factor a trinomial.
10((1 + -7b)(1 + -7b)) = 0

Ignore the factor 10.

Subproblem 1

Set the factor '(1 + -7b)' equal to zero and attempt to solve: Simplifying 1 + -7b = 0 Solving 1 + -7b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -7b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -7b = 0 + -1 -7b = 0 + -1 Combine like terms: 0 + -1 = -1 -7b = -1 Divide each side by '-7'. b = 0.1428571429 Simplifying b = 0.1428571429

Subproblem 2

Set the factor '(1 + -7b)' equal to zero and attempt to solve: Simplifying 1 + -7b = 0 Solving 1 + -7b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -7b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -7b = 0 + -1 -7b = 0 + -1 Combine like terms: 0 + -1 = -1 -7b = -1 Divide each side by '-7'. b = 0.1428571429 Simplifying b = 0.1428571429

Solution

b = {0.1428571429, 0.1428571429}

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